BL/CH401

EXAM II - Answers


1. Kinetics Problem - 50 Points.

Km = 0.2 mM

Vmax = 75 micromol/min

Inhibitor A = Non-Competitive

Km' = 0.2 mM

Vmax' = 25 micromol/min

At [I] = [A] = 10 microM, Ki = 5 microM.

Inhibitor B = Competitive

Km' = 0.4 mM

Vmax' = 75 micromol/min

At [I] = [B] = 300 microM, Ki = 300 microM.

2. Protein Structure - 40 Points.

See lecture notes for Lectures 8 and 9.

3. Thought Problem - 10 Points.

Methanol and ethanol are both substrates for alcohol dehydrogenase. So, when ethanol is given to a person with methanol poisoning, ethanol will act as a competitive inhibitor and thereby prevent (at least dramatically slow) the catalytic conversion of methanol to formaldehyde, which presumably causes the damage in methanol poisoning.


©Wilbur H. Campbell, 1995; wcampbel@mtu.edu

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